rem和mod的區別
我不清楚rem和mod兩種運算是否遵從什麼標準，也不瞭解它們從何而來，不過對於LISP來說，它是有標準的就OK了。它們對負數的運算方式也不難記憶，在此我只是提供一種記憶的方法。
細說rem＆mod（remainder＆modulo）
大家先來回顧一下小學學過的除法運算，被除數除以除數，得到商和餘數（只考慮整數運算）：
a ÷ b ＝ q … r
r ＝ a - q × b
而取模運算，就是只要得到那個餘數r就可以了。
其實要記憶好rem和mod處理負數時的區別，也要考慮下那個商q的。正負相除得負，負負相除得正，這就是得到q的規律。r是最後才來確定的。下面就開始講解rem和mod吧。
rem：使商向「內」取整
向「內」取整是什麼意思呢？就是指讓商的絕對值儘量小，就像用truncate函數把不求餘的商的絕對值的小數部分截掉一樣。就舉例說明吧：
7 ÷ 3 ≈ 2.3
7
rem3 ＝ 2 … 17
rem-3 ＝ -2 … 1-7
rem3 ＝ -2 … -1-7
rem-3 ＝ 2 … -1
明白了吧？我就不廢話了。
mod：使商向「下」取整
向「下」取整即讓商的值儘量小（不是說絕對值），如經過floor函數處理一樣。例：
7 ÷ 3 ≈ 2.3
7
mod3 ＝ 2 … 17
mod-3 ＝ -3 … -2-7
mod3 ＝ -3 … 2-7
mod-3 ＝ 2 … -1
OK，解說完畢。
其它資料
或許大家已經發現，對於rem來說，餘數的符號與被除數的相等，而mod的則是與除數相等。
另外可到此處瞭解：http://www.franz.com/support/documentation/8.1/ansicl/dictentr/modrem.htm
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Dec 07, 2011 10:18:11 PM
racket里
分别叫做remainder和modulo
> (remainder 1 3)
1
> (modulo 1 -3)
-2
> (remainder 1 -3)
1
remainder叫做取余.modulo叫做取模...
Dec 07, 2011 11:12:21 PM
-_-;感覺都一個意思，「模」好像是mo的擬聲。Racket竟然會用這麼完整的名稱啊……嗯，從結果看來，是同一標準的。
Aug 06, 2022 10:42:58 PM
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